If the sum of m consecutive odd integers is m4, then the first integer term is
A
m3−m−1
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B
m3−m+1
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C
m3+m−1
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D
2m3−m+12
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Solution
The correct option is Cm3−m+1 The m consecutive terms is an A.P. with its first term being a and common difference being 2. ⇒m4=m2[2a+(m−1)×2] m4=m(a+m−1) m3−m+1=a