If the sum of n positive integers $K_{1}, K_{2}, K_{3}, . . . ., K_{n}$ is an even number, then number of odd integers involved in the expresssions is

odd

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even

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(n - 1)

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none of these.

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Solution

The correct option is B even
When odd number are added even number of times the resultant is always an even number.

For example:

3+5=8 $\to$ even

3+5+9=17 $\to$ odd

3+5+9+13=30 $\to$ even etc.

Again, even+even=even

and odd+even=odd.

So, the sum of odd numbers cannot be odd in order for the resultant sum to be an even number.

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If the sum of n positive integers K1,K2,K3,....,Kn is an even number, then number of odd integers involved in the expresssions is

If the sum of n positive integers $K_{1}, K_{2}, K_{3}, . . . ., K_{n}$ is an even number, then number of odd integers involved in the expresssions is