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Question

If the sum of n term of an AP is 3n2+5n then find its nth term.

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Solution

Sn=3n2+5n
Sn1=3(n1)2+5(n1)
=3(n22n+1)+5n5
=3n26n+3+5n5
=3n2n2
tn=SnSn1
=3n2+5n(3n2n2)
=3n2+5n3n2+n+2
=6n+2
the nth term is 6n+2

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