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Question

If the sum of n terms of an A.P. is 2 n2 + 5 n, then its nth term is
(a) 4n − 3
(b) 3 n − 4
(c) 4 n + 3
(d) 3 n + 4

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Solution

(c) 4 n + 3

Sn=2n2+5nS1=2.12+5.1 = 7 a1=7Sn=2.22+5.2=18 a1+a2=18 a2=11Common difference, d =11-7= 4an=a+n-1d =7+n-14 =4n+3

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