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Question

If the sum of 'n' terms of an A.P is (pn+qn2) where p and q are constant find the common difference

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Solution

Given : Sn=pn+qn2.......(1)
Substituting n=1,2we get
S1=p(1)+q(1)2=p+q and
S2=p(2)+q(2)2=2p+4q
We know that , S1=a
S2=a+d
S2S1=(a+d)(a)=d.......(2)
S2S1=(2p+4q)(p+q)....(3)
From (1)and (2)
p+3q=d


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