If the sum of odd numbered terms and the sum of even numbered terms in the expansion of (x+a)n are A and B respectively, then the value of (x2−a2)n is
A2−B2
A2−B2
If A and B denote respectively the sum of odd terms and even terms in the expansion (x+a)n
Then, (x+a)n=A+B....(1)
(x−a)n=A−B....(2)
Multiplying both the equations we get
(x+a)n(x−a)n=A2−B2
⇒(x2−a2)n=A2−B2