Question

If the sum of opposite angles of a paarallelogram is ${120}^{\circ }$ Find the all its angles.

Answer 1

Sum of opposite angles of parallelogram is $120$

Let x be opposite angle of parallelogram. [opp 2s of parallelograms are equal]

$2x=120$

$[x={60}^o]$

Now two angle of Parallelogram are $={60}^o$ each

Now, let y be adjacent angle of parallelogram to ${60}^o$, then

${60}^o+y=180$

$[y={120}^o]$

$\therefore$ Angles of parallelogram are ${60}^o,{60}^o,{120}^o$ & ${120}^o$.