The correct option is D -(p + q)
let first term be aand common difference be d
so pthterm=a+(p−1)d
and sum of first p terms=p2(2a+(p−1)d)=q
hence(2a+(p−1)d)=2qp....(1)and qthterm=a+(q−1)d
and sum of first q terms=q2(2a+(q−1)d)=phence(2a+(q−1)d)=2pq....(2)subtract (1) from (2)(p−q)d=2(qp−pq)=2(q2−p2)qso,d=−2(p+q)pq....(3)(p+q)thterm=(a+(p+q−1)d)and sum of its first(p+q)term=(p+q)2(2a+(p+q−1)d)=(p+q)2(2a+(p−1)d+qd)=(2qp+qd)(p+q)2...from(1)=(2qp−2−2qp)p+q2...from(3)=−(p+q)