If the sum of successor and predecessor of a number is 14, the number should be
7
Let the number be x.
Therefore, the successor of number is (x+1) and the predecessor is (x−1).
Given that the sum of successor and predecessor is 14.
∴x+1+x−1=14⇒2x=14⇒x=142⇒x=7
So, the number should be 7.