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Area of a Circle

If the sum of...

Question

If the sum of the areas of two circles with radii R₁ and R₂ is equal to the area of a circle of radius R, then

R₁ + R₂ < R

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R₁² + R₂² = R²

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R₁ + R₂ = R

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R₁²+ R₂² < R²

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Solution

The correct option is B
R₁² + R₂² = R²

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Similar questions

R_{1}

R_{2}

R_{1} + R_{2} = R

R_{1}^{2} + R_{2}^{2} = R^{2}

R_{1} + R_{2} < R

R_{1}^{2} + R_{2}^{2} < R_{2}

If the sum of the areas of two circles with radii $R_{1}$ and $R_{2}$ is equal to the area of a circle of radius R then

(a) $R_{1} + R_{2} = R$

(b) $R_{1} + R_{2} > R$

(d) $R_{1}^{2} + R_{2}^{2} = R^{2}$

R_{1} + R_{2} = R

R_{1} + R_{2} < R

R_{1}^{2} + R_{2}^{2} < R^{2}

R_{1}^{2} + R_{2}^{2} = R^{2}

If the sum of the areas of two circles with radii R₁ and R₂ is equal to the area of a circle of radius R, then

r_{1}

r_{2}

r

r = r_{1} + r_{2}

{r_{1}}^{2} + {r_{2}}^{2} = r^{2}

r_{1} + r_{2} < r

{r_{1}}^{2} + {r_{2}}^{2} < r^{2}

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