If the sum of the circumferences of the two circles with radii r1 and ra is equal to the circumference of a circle of radius r- then - a r - r 1- r 2 b r 1- r 2- r c r 1- r 2- r -d None of these

The circumference of the circle with radius r = circumference of the circle with radius nbsp;r1+ nbsp;circumference of the circle with radius nbsp;r2 2 ...

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Standard X

Mathematics

Circumference

If the sum of...

Question

If the sum of the circumferences of the two circles with radii $r_{1}$ and $r_{2}$ is equal to the circumference of a circle of radius $r$ , then
(a) $r = r_{1} + r_{2}$ (b) $r_{1} + r_{2} > r$ (c) $r_{1} + r_{2} < r$ (d) None of these

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Solution

The circumference of the circle with radius r = circumference of the circle with radius $r_{1}$ + circumference of the circle with radius $r_{2}$
$2 πr = 2 {πr}_{1} + 2 {πr}_{2} \Rightarrow r = r_{1} + r_{2}$
Hence, the correct answer is option (a).

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If the sum of the circumferences of the two circles with radii r1 and r2 is equal to the circumference of a circle of radius r, then (a) r = r1 + r2 (b) r1 + r2 > r (c) r1 + r2 < r (d) None of these

The circumference of the circle with radius r = circumference of the circle with radius r1+ circumference of the circle with radius r2 2πr=2πr1+2πr2⇒r=r1+r2 Hence, the correct answer is option (a).

If the sum of the circumferences of the two circles with radii $r_{1}$ and $r_{2}$ is equal to the circumference of a circle of radius $r$ , then
(a) $r = r_{1} + r_{2}$ (b) $r_{1} + r_{2} > r$ (c) $r_{1} + r_{2} < r$ (d) None of these

The circumference of the circle with radius r = circumference of the circle with radius $r_{1}$ + circumference of the circle with radius $r_{2}$
$2 πr = 2 {πr}_{1} + 2 {πr}_{2} \Rightarrow r = r_{1} + r_{2}$
Hence, the correct answer is option (a).