If the sum of the circumferences of two circles with diameters $d_{1}$ and $d_{2}$ is equal to the circumference of a circle of diameter d, then

d_{1}^{2} + d_{2}^{2} = d^{2}

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d_{1} + d_{2} = d

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d_{1} + d_{2} > d

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d_{1} + d_{2} < d

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Solution

The correct option is B $d_{1} + d_{2} = d$
Circumference = $π \times$ diameter.
Here, $π d = π d_{1} + π d_{2}$
$∴ d = d_{1} + d_{2}$
$\Rightarrow$ the required diameter is equal to $d_{1} + d_{2} .$

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If the sum of the circumferences of two circles with diameters d1 and d2 is equal to the circumference of a circle of diameter d, then

The correct option is B d1+d2=dCircumference = π× diameter.Here, πd=πd1+πd2∴d=d1+d2⇒ the required diameter is equal to d1+d2.

If the sum of the circumferences of two circles with diameters $d_{1}$ and $d_{2}$ is equal to the circumference of a circle of diameter d, then

The correct option is B $d_{1} + d_{2} = d$
Circumference = $π \times$ diameter.
Here, $π d = π d_{1} + π d_{2}$
$∴ d = d_{1} + d_{2}$
$\Rightarrow$ the required diameter is equal to $d_{1} + d_{2} .$