If the sum of the coefficients in the expansion of (a2x2-6ax+11)10, where a is constant is 1024, then the value of a is:
5
1
2
3
4
Explanation for the correct option.
The given expression is (a2x2-6ax+11)10.
For the sum of coefficients, we will take x=1.
⇒(a2-6a+11)10=1024⇒(a2-6a+11)10=210⇒a2-6a+11=2⇒a2-6a+9=0⇒a-32=0⇒a=3
Hence, option D is correct.