If the sum of the coefficients in the expansion of (1–3x+10x2)n is a and if the sum of the coefficients in the expansion (1+x2)n is b, then,
A
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B
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C
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D
None of these
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Solution
The correct option is B We have a = sum of the coefficient in the expansion of (1−3x+10x2)n=(1−3+10)n=(8)n ⇒(1−3x+102)n=(2)3n,[putting x=1] Now, b = sum of the coefficients in the expansion of (1+x2)n=(1+1)n=2n. Clearly,a=b3