If the sum of the coefficients in the expansion of (1−3x+10x2)n is a and if the sum of the coefficients in the expansion of (1+x2)n is b, then
A
a=3b
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B
a=b3
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C
b=a3
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D
3a=b
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Solution
The correct option is Ba=b3 We have, a= sum of the coefficients in the expansion of (1−3x+10x2)n=(1−3+10)n=(8)n=(2)3n (by putting x=1) Now, b= sum of the coefficients in the expansion of (1+x2)n