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Question

If the sum of the coefficients in the expansion of (1−3x+10x2)n is a and if the sum of the coefficients in the expansion of (1+x2)n is b, then

A
a=3b
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B
a=b3
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C
b=a3
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D
3a=b
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Solution

The correct option is B a=b3
We have, a= sum of the coefficients in the expansion of (13x+10x2)n
=(13+10)n=(8)n=(2)3n
(by putting x=1)

Now, b= sum of the coefficients in the expansion of (1+x2)n
=(1+1)n=2nClearly ,a=b3

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