If the sum of the coefficients in the expansion of (a2x2−2ax+1)51 vanishes, then the value of a is
A
2
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B
−1
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C
1
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D
−2
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Solution
The correct option is C1 (a2x2−2ax+1)51=(ax−1)102 Now for sum of the coefficient put the value of x=1 Hence sum of the coefficient =(a−1)102 Now for sum of the coefficients to be 0 a=1