wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the sum of the first 40 term of the series 3+4+8+9+13+14+18+19+ is 102(m), then the value of m is

A
25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 20
Let S=(3+4)+(8+9)+(13+14)+(18+19)+
S=7+17+27+37+upto 20 terms
The terms of S are in A.P.
Here a=7,d=10,n=20
S=202[(2×7)+(19×10)] (Sn=n2[(2a+(n1)d)])
=202×204
=20×102
m=20

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon