If the sum of the first $^{'} n^{'}$ terms of a sequence is $4 n^{2} + 5 n,$ then the general term of the sequence is

8 n + 1

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4 n - 1

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4 n^{2} + 5 n

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6 n + 3

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Solution

The correct option is A $8 n + 1$
$S_{n} = 4 n^{2} + 5 n$
General term of the sequence $T_{n} = S_{n} - S_{n - 1}$
$T_{n} = S_{n} - S_{n - 1} = 4 n^{2} + 5 n - (4 (n - 1)^{2} + 5 (n - 1))$
$T_{n} = 8 n + 1$

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