If the sum of the radius and the height of a closed cylinder is 45 cm and the total surface area of the cylinder is $1540 c m^{2}$ , then the circumference of the base of the cylinder is:

66 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

44 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

56 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Can't be determined

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 44 cm
$2 π r (r + h) = 1540 c m^{2} a n d (r + h) = 35 c m ∴ 2 π r = \frac{1540}{35} = 44 c m$

Suggest Corrections

Similar questions

1540 {c m}^{2}

The curved surface area of a cylinder is 2200 sq cm and circumference of its base is 220 cm. Then the height of the cylinder is:

1628 c m^{2}

37 m

1628 m^{2}

Join BYJU'S Learning Program