If the sum of the squares of the distance of a point from the three co-ordinate axes be 36,then its distance from origin
3√2
Let P(x.y,z). Now under given condition we get [√(x2+y2)]2+[√(y2+z2)]2+[√(z2+x2)]2=36
⇒ x2+y2+z2=18
Then distance from origin to the point (x, y, z) is
√x2+y2+z2=√18=3√2.