If the sum of the two roots of the equation $4 x^{3} + 16 x^{2} - 9 x - 36 = 0$ is zero, then the roots are

1, 2 -2

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Solution

The correct option is D

Given equation $4 x^{3} + 16 x^{2} - 9 x - 36 = 0$ ,

putting x = -4 ⇒ -4× 64+256+36-36=0

Hence x =-4 is a root of the equation

Now reduced equation is $4 x^{2} (x + 4) - 9 (x + 4) = 0$

⇒ $(x + 4) (4 x^{2} - 9) = 0$ ⇒ x = -4, x = ± $\frac{3}{2}$

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4 x^{3} + 16 x^{2} - 9 x - 36 = 0

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