Question

If the sum of the zeros of the polynomial f(x) = 2x³ − 3kx² + 4x − 5 is 6, then the value of k is

(a) 2
(b) 4
(c) −2
(d) −4

Answer 1

Let, be the zeros of the polynomial and we are given that
$\alpha +\beta +\gamma$=.

Then,

$$\begin{gathered} \alpha +\beta +\gamma =\frac{-\mathrm{Coefficient}\mathrm{of}x}{\mathrm{Coefficient}\mathrm{of}{x}^2} \\ =-\frac{(-3k)}{2}=\frac{3k}{2} \end{gathered}$$

It is given that

$\alpha +\beta +\gamma$=

Substituting $\alpha +\beta +\gamma =\frac{3k}{2}$, we get

The value of k is.

Hence, the correct alternative is