Question

If the sum of three consecutive integers is $72$, then the largest of the three integers is

Answer 1

$\underset{–}{\text{Given:}}$
Sum of three consecutive integers $=72$

Let the smallest integer be $a.$
Consecutively, the larger integers would be $(a+1)\&(a+2).$

Now, according to the question:
$a+(a+1)+(a+2)=72$
$\Rightarrow 3a+3=72$
$\Rightarrow 3a+3-3=72-3$
$\Rightarrow 3a=69$
$\Rightarrow \frac{3a}{3}=\frac{69}{3}$
$\Rightarrow a=23$

$\therefore$ The largest integer $=a+2$
$=23+2$
$=\underset{–}{25}.$