If the sum of three consecutive integers is $75$ , then the largest of the three integers is

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Solution

Given that the sum of three consecutive integers is $75$
Let the smallest integer of the 3 consecutive integers be $a$
Consecutively, larger integers would be $(a + 1) & (a + 2)$
$\Rightarrow a + (a + 1) + (a + 2) = 75$
$\Rightarrow 3 a + 3 = 75$
Subtract $3$ from both sides of the equation
$\Rightarrow 3 a + 3 - 3 = 75 - 3$
$\Rightarrow 3 a = 72$
Divide by 3 on both sides of the equation
$\Rightarrow \frac{3 a}{3} = \frac{72}{3} \Rightarrow a = 24$
$∵$ The largest integer of the 3 consecutive integers is $a + 2$
$\Rightarrow a + 2 = 24 + 2 = 26$

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If the sum of three consecutive integers is 75, then the largest of the three integers is

If the sum of three consecutive integers is $75$ , then the largest of the three integers is