Question

If the sum of three consecutive multiples of 4 is 444, then these multiples are 144, 148, 152.

• A. 144, 148, 152
• B. 100, 104, 108

Answer 1

The correct option is A

144, 148, 152

Let us assume the first multiple of 4 as 4x. Hence, the next two multiples are 4x + 4 and 4x + 8

According to the question,

$4x+(4x+4)+(4x+8)=444$

$\Rightarrow 12x+12=444$
$\Rightarrow 4(3x+3)=4\left(111\right)$

$\Rightarrow 3x+3=111$

$\Rightarrow 3x=108$

$\Rightarrow$ x = 36

$⟹4x=4\times 36=144$,
$4x+4=144+4=148$ and
$4x+8=144+8=152$

Therefore, the multiples are 144, 148 and 152.