Question

If the sum of three consecutive multiples of $9$ is $108$, then find the second multiple.

• A. $3$
• B. $45$
• C. $27$
• D. $36$

Answer 1

The correct option is D $36$

According to the question,
$9x+9(x+1)+9(x+2)=108$
$\Rightarrow x+(x+1)+(x+2)=\frac{108}{9}=12$
$\Rightarrow 3x+3=12$
$\Rightarrow 3x=12-3=9$
$\Rightarrow x=\frac{9}{3}=3$
The consecutive multiples are:
$9x=27,9(x+1)=36,9(x+2)=45$

Hence, the three consecutive multiples are $27,36,$ and $45$.
$\therefore$ The second multiple is $36$.