If the sum of three consecutive numbers is 39, find the numbers.
Let the smallest number be 'x′.
So, the other two numbers can be written as x+1 and x+2.
Given, x+(x+1)+(x+2)=39⇒3x+3=39⇒3x=39−3=36⇒x=363=12
Since x=12,x+1=13 and x+2=14
Thus, the numbers are 12, 13 and 14.