Question

If the sum of three consecutive numbers is 39, then find those numbers.

Answer 1

Let the smallest number be '$x$'
Since, we are considering the consecutive numbers, the other two numbers are $x+1$ and $x+2$.$\left[1mark\right]$
$x+(x+1)+(x+2)=39\Rightarrow 3x+3=39\Rightarrow 3x=39-3\Rightarrow 3x=36\Rightarrow x=\frac{36}{3}\Rightarrow x=12$

Thus, the numbers are 12, 12+1, and 12+2.
12, 13 and 14 are the required numbers.$\left[1mark\right]$