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Question

If the sum of three consecutive terms of an A.P is 51 and the product of last and first term is 273, then the numbers


A

21,17,13

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B

20,16,12

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C

22,18,14

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D

24,20,16

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Solution

The correct option is A

21,17,13


Step 1: Find the a.

Let a-d, a and a+dbe the three numbers.

Sum3a=51a=51/3a=17

Step 2: Find the d.

Given the product of last and first term =273

(a-d)(a+d)=273a2-d2=273289d2=273d2=16d=4

Therefore, the numbers are 21,17,13.

Hence, option A is the correct answer.


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