Question

If the sum of three numbers is 190. If the ratio of first two numbers is 2:3 and the last two is 4:6. Find the smallest number.

• A. 90
• B. 40
• C. 60
• D. 70
• E. 20

Answer 1

The correct option is B

40

Let the three numbers be a,b,c

a = $\frac{2}{3}$ b

c = $\frac{3}{2}$b

$\frac{2}{3}$ b + b + $\frac{3}{2}$b = 190

$\frac{4b+6b+9b}{6}=190$

b = 60 a = 40 c = 90