Question

If the sum of two consecutive integers is $15$, find their product.

• A. $36$
• B. $48$
• C. $56$
• D. $64$

Answer 1

Answer: (C)

$56$

Let the smaller number be $n$.

Hence, the numbers will be $n,(n+1)$.
Therefore applying conditions:

$n+(n+1)=15$

$\Rightarrow 2n=14$

$\Rightarrow n=7$

Therefore the two numbers would be $7,8$.
Hence, their product will be $n(n+1)=7\left(8\right)=56$.