If the sum of two numbers p and q is √10 and their difference is √6, then the value of logqp is
A
−1
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B
0
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C
1
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D
2
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Solution
The correct option is A−1 Given conditions, p+q=√10⇒(p+q)2=10⇒p2+q2+2pq=10⋯(1) p−q=√6⇒p2+q2−2pq=6⋯(2) Subtracting equation (2) from (1), we get 4pq=4 ⇒pq=1 ⇒p=1q Taking logq on both sides, we get logqp=logq1q=−1