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Question

If the sum of two of the roots of x3+px2+qx+r=0 is zero, then pq =


A

- r

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B

r

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C

2 r

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D

- 2 r

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Solution

The correct option is B

r


Given that, α + β = 0

α + β + γ = -p ⇒ γ = -p

Substituting γ = -p in the given equation

p3+p3pq+r=0 ⇒ pq =r


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