If the sum of two of the roots of $x^{3} + p x^{2} + q x + r = 0$ is zero, then pq =

- r

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2 r

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- 2 r

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Solution

The correct option is B
r

Given that, α + β = 0

α + β + γ = -p ⇒ γ = -p

Substituting γ = -p in the given equation

⇒ $- p^{3} + p^{3} - p q + r = 0$ ⇒ pq =r

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Similar questions

If the sum of two of the roots of $x^{3} + p x^{2} + q x + r = 0$ is zero, then pq =

x^{3} + p x^{2} + q x + r = 0

x^{3} - p x^{2} + q x - r = 0

α, β, γ

x^{3} + p x^{2} + q x + r = 0

\sum α^{3} β^{3}

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