If the sums of n terms of two arithmetic progressions are in the ratio 3n+5:5n-7, then their nth terms are in the ratio
(a) 3n-15:n-1
(b) 3n+15:n+1
(c) 5n+13:n+1
(d) 5n-13:n-1
In the given problem, the ratio of the sum of n terms of two A.P’s is given by the expression,
We need to find the ratio of their nth terms.
Here we use the following formula for the sum of n terms of an A.P.,
Where; a = first term for the given A.P.
d = common difference of the given A.P.
n = number of terms
So,
Where, a and d are the first term and the common difference of the first A.P.
Similarly,
Where, a’ and d’ are the first term and the common difference of the first A.P.
So,
Equating (1) and (2), we get,
Now, to find the ratio of the nth term, we replace n by. We get,
As we know,
Therefore, we get,
Hence the correct option is (b).