Question

If the supplement of an angle is ${130}^{\circ }$, then find its complement.

Answer 1

Supplement of an angle = ${130}^o$

Let the angle be $x^o$

Then, $x^o+{130}^o={180}^o$

$\therefore x={50}^o$

Now, complement of the angle = ${90}^o-x={90}^o-{50}^o$

$={40}^o$