1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# If the surface area of cube A is 64% of the surface area of cube B, then the volume of cube A is 'k' percent of the volume of cube B. The value of 'k' is

A
0.64
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
0.512
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
51.2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
64
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C 51.2Total surface area of a cube of edge a =6a2 Let side of cube A be A and side of cube B be B. Given 6A2=64100×6B2=>A=810BVolume of a cube =side3Hence, Volume of cube A $= {A}^{3} ={(\dfrac{8}{10} B)}^{3} = \dfrac{512}{1000}{B}^{3}$Volume of cube A =B3Given, 5121000B3= k % ×B3=> k % =5121000=>k=5121000×100=51.2

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Total Surface Area of a Cuboid
MATHEMATICS
Watch in App
Join BYJU'S Learning Program