If the symmetry is such that you can find a surface on which the electric field is constant, then evaluating the electric flux can be done by

dividing the value of the field by the area of the Gaussian surface.

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multiplying the value of the field times the area of the Gaussian surface.

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multiplying the square of the value of the field times the area of the Gaussian surface.

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dividing the square of the value of the field times the area of the Gaussian surface.

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Solution

The correct option is B multiplying the value of the field times the area of the Gaussian surface.
From gauss law, Flux through the surface, $ϕ$ is
$ϕ = \oint \to E . - \to d S$

If the electric field is constant over the surface, then it can be taken out of the integration sign.
$ϕ = \to E \int - \to d S$
$\int - \to d S =$ Area of gaussian surface
Then flux $=$ Electric field times the area of gaissian surface.

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