If the system of equations 4x+py=21 and px−2y=15 has unique solutions then which of following is true?
Consider the given equation.
4x+py=21
px−2y=15
The general equation,
a1x+b1y=c1
a2x+b2y=c2
So,
a1=4,b1=p,c1=21
a2=p,b2=−2,c2=15
We know the condition of unique solution
a1a2≠b1b2
Therefore,
4p≠p−2
p2≠−8
p≠2√−2
So, p is any real value except 2√−2.
Hence, this is the answer.