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Question

If the system of equations 4x+py=21 and px2y=15 has unique solutions then which of following is true?

A
p22
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B
p22
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C
p2
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D
p2
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Solution

The correct option is D p22

Consider the given equation.

4x+py=21

px2y=15

The general equation,

a1x+b1y=c1

a2x+b2y=c2

So,

a1=4,b1=p,c1=21

a2=p,b2=2,c2=15

We know the condition of unique solution

a1a2b1b2

Therefore,

4pp2

p28

p22

So, p is any real value except 22.

Hence, this is the answer.


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