If the system of equations ax + y = 3, x + 2y =3, 3x + 4y =7 is consistent, then value of a is equal to

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Solution

The correct option is A
2

The intersection point of x + 2y =3 and 3x + 4y = 7 is (1, 1). For consistent , point (1, 1) satisfies the equation

ax + y = 3

∴ a + 1 =3

⟹a = 2

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Similar questions

a x + y = 3, x + 2 y = 3, 3 x + 4 y = 7

a

a x + y = 3, x + 2 y = 3, 3 x + 4 y = 7

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a x + y = 3, x + 2 y = 3

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x + 2 y - 3 = 0

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x + 2 y \leq 3, 3 x + 4 y \geq 12, x \geq 0, y \geq 1

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