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Question

If the system of equations
kx+y+2z=1
3xy2z=2
2x2y4z=3
has intinitely many solutions, then k is equal to

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Solution

D=0
∣ ∣k12312224∣ ∣
k(44)1(124)+2(62)
1616=0
Also. D1=D2=D3=0
D2=∣ ∣k12322234∣ ∣
k(8+6)1(124)+2(9+4)=0
2k+16+26=0
2k=42
k=21

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