MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Determinant

If the system...

Question

If the system of equations of $3 x - 2 y + z = 0, k x - 14 y + 15 z = 0, x + 2 y + 3 z = 0$ has non trivial solution then $k =$

A

29

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

26

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

23

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

19

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $29$
According to the given information

$\Rightarrow ∣ ∣ ∣ ∣ \begin{matrix} 3 & - 2 & 1 k & - 14 & 15 1 & 2 & 3 \end{matrix} ∣ ∣ ∣ ∣ = 0$

$\Rightarrow 3 (- 42 - 30) + 2 (3 k - 15) + 1 (2 k + 14) = 0$

$\Rightarrow - 216 + 6 k - 30 + 2 k + 14 = 0$

$\Rightarrow 8 k = 232$

$\Rightarrow k = 29$

Suggest Corrections

thumbs-up

0

Similar questions

Q. If the system of equations

3 x - 2 y + z = 0, λ x - 14 y + 15 z = 0, x + 2 y - 3 z = 0

have non zero solution, then find

λ

Q. The value(s) of

k \in R

for which the system of equations

x + k y + 3 z = 0,

k x + 2 y + 2 z = 0

2 x + 3 y + 4 z = 0

admits a non-trivial solution, is

Q. System of equations

x + 2 y + z = 0, 2 x + 3 y - z = 0

(t a n θ) x + y - 3 z = 0

has non-trivial solution then number of value(s) of

θ ϵ (- π, π)

Q. If the system of equations

x - k y - z = 0, k x - y - z = 0

x + y - z = 0

has a non-trivial solution, then

k

Q. System of equations

x + 2 y + z = 0, 2 x + 3 y - z = 0

(tan θ) x + y - 3 z = 0

has non-trivial solution, then number of values(s) of

θ \in (- π, π)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon