If the tangent and normal to xy=a2 at a point cut off intercepts a1,a2 and b1,b2 on the x- axis and y-axis respectively then a1a2+b1b2=
A
0
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B
a2
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C
1
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D
−1
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Solution
The correct option is D0 Assume rectangular hyperbola is xy=c2 Thus equation of tangent and normal at any point 't' are, xt+ty=2c and y−ct=t2(x−ct) Now putting y=0 in both the equation we get, a1=2ct,a2=ct−ct3 and putting x=0 we get, b1=2ct,b2=ct−ct3 ⇒a1a2+b1b2=2ct(ct−ct3)+2ct(ct−ct3)=0