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Question

If the tangent and normal to xy=a2 at a point cut off intercepts a1, a2 and b1, b2 on the x- axis and y-axis respectively then a1a2+b1b2=

A
0
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B
a2
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C
1
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D
1
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Solution

The correct option is D 0
Assume rectangular hyperbola is xy=c2
Thus equation of tangent and normal at any point 't' are,
xt+ty=2c and yct=t2(xct)
Now putting y=0 in both the equation we get, a1=2ct,a2=ctct3
and putting x=0 we get, b1=2ct,b2=ctct3
a1a2+b1b2=2ct(ctct3)+2ct(ctct3)=0

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