If the tangent at a point P, with parameter t, on the curve x=4t2+3,y=8t3−1,tϵR meets the curve again at a point Q, then the coordinates of Q are:
A
(t2+3,−t3−1)
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B
(4t2+3,−8t3−1)
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C
(16t3+3,−64t3−1)
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D
(t2+3,t3−1)
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Solution
The correct option is A(t2+3,−t3−1) dxdt=8t and dydt=24t2 dydx=3t y−y1=m(x−x1) y−(8t3−1)=3t(x−4t2−3) Equation is y=3tx−4t3−9t−1 We can subsitute and check that option A satisfies the equation.