If the tangent at the point P on the circle x2+y2+6x+6y=2 meets the straight line 5x−2y+6=0 at point Q on the y-axis, then the length of PQ is
A
4 units
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B
2√5 units
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C
5 units
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D
3√5 units
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Solution
The correct option is C5 units 5x−2y+6=0 y-intercept of the line is Q(0,3).
So tangent at P on x2+y2+6x+6y−2=0 passes through Q(0,3) as per the given condition.
∴PQ= length of tangent to circle from (0,3) =√S1=5 units