If the tangent to the curve y=ex at a point (c,ec) and the normal to the parabola y2=4x at the point (1,2) intersect at the same point on the x-axis, then the value of c is
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Solution
For (1,2) of y2=4x ⇒t=1,a=1
Equation of normal ⇒tx+y=2at+at3 ⇒x+y=3 intersect x-axis at (3,0)
y=ex ⇒dydx=ex
Tangent at point (c,ec) is ⇒y−ec=ec(x−c)
at (3,0)⇒0−ec=ec(3−c) ∴c=4