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Question

If the tangent to the graph of the function y=f(x) makes angles of π/4 and π/3 with the xaxis at the points x=2 and x=4 respectively, then the value of 42f(x)f′′(x)dx=

A
0
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B
2
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C
3
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D
1
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Solution

The correct option is D 1
we know tangent to the curve y=f(x) at x=2,x=4 make angle

π4 and π3 respectively then we must have

f(x)=tanθ put x=2,θ=π/4

f(2)=1 put x=4,θ=π/3

f(4)=3

consider

42f(x)f(x)dx let

31tdt=t2231

f(x)=t
f(x)dx=dt
=3212=1

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