If the tangents drawn from a point to the parabola y2=4ax are also normals to the parabola x2=4by, then
A
b2≥8a2
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B
b2≥2a2
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C
a2≥2b2
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D
a2≥8b2
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Solution
The correct option is Da2≥8b2 The equation of a tangent to y2=4ax is y=mx+am⋯(1)
This is a normal to the parabola x2=4by,
So any normal to the parabola is given by y=mx+2b+bm2⋯(2)
Comparing equation (1) and (2), we get am=2b+bm2⇒2bm2−am+b=0
As m∈R, so D≥0⇒a2−8b2≥0⇒a2≥8b2